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	Problem	Probable Cause	Possible Solution
1	Not able to add new checklist items. Here is what is logged in the browser consolde PUT https://[instance]/rest/railsware/1.0/checklist/-1/item 500 {errorMessage: "bundle [com.railsware.rw-smart-checklist-biz]"}	This error can happen anytime the database user has not be granted the needed permissions, and JIRA is expected to create a new foreign key constraint. Explained here https://confluence.atlassian.com/jirakb/com-mysql-jdbc-exceptions-jdbc4-mysqlsyntaxerrorexception-references-command-denied-to-user-872266070.html	Grant proper permisisons to Jira User by executing SQL command Code Block GRANT SELECT,INSERT,UPDATE,DELETE,CREATE,DROP,REFERENCES,ALTER,INDEX on <JIRADB>.* TO '<USERNAME>'@'<JIRA_SERVER_HOSTNAME>' IDENTIFIED BY '<PASSWORD>'; Note: you can use 3rd party addon, like Database Explorer in order to execute these queries
2	Checklist statuses are not available	Conflict with settigns left after prevous version of Smart Addon that was installed on this instance	Stop the Jira instance Delete the following hidden plugin cache directories (just these two): JIRA_HOME/plugins/.bundled-plugins JIRA_HOME/plugins/.osgi-plugins Restart JIRA
3	"Uncaught DOMException: Permission denied to access property "document" on cross-origin object" in the JavaScript” message appears when trying an import checklist from a Template Jira version 8.12	Known bug introduced by Atlassian in Jira v 8.12 Fixed in Jira 8.12.3, 8.13.1 More details: https://jira.atlassian.com/browse/JRASERVER-71747	Upgrade your Jira to 8.12.3, 8.13.1 or higher version.
4	Checklist item could not be added. The following error shown in Jira log: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Specified key was too long; max key length is 767 bytes at com.atlassian.activeobjects.internal.EntityManagedActiveObjects.migrate(EntityManagedActiveObjects.java:53) at com.railsware.ao.upgrade.v2.MigrateProjectTemplates.upgrade(MigrateProjectTemplates.java:59) at com.atlassian.activeobjects.internal.ActiveObjectUpgradeManagerImpl$1.doInTransaction(ActiveObjectUpgradeManagerImpl.java:68) at Reproduced on Jira v7.6 MySQL DataBase v5.7	MySQL DB was not set properly	Check if mysql DB has set as suggested by Atlassian: https://confluence.atlassian.com/adminjiraserver/connecting-jira-applications-to-mysql-5-7-966063305.html Especially character_set_server=utf8mb4 innodb_large_prefix=ON
5	Using “Clone” Issue doesn’t copy “Checklists” field content to the newly created issue.	“Checklists” field is not added to the Projects, where Clone operation is executed.	Go to Issues → Custom Fields → search for ”Checklists“ field → Configure Check Applicable contexts for scheme Click “Edit Configuration” Go to “Choose applicable context” Make sure there selected  “Global context. Apply to all issues in Jira.” Even if it is - Click “Modify” Now, the cloning should work properly Note: For users who started using checklist fro m version 5.5.0 that should already been fixed.

How to fix the duplication of checklist items that happened after applying a template?

The issue is reproduced if a template was created using app version 7.0.0, and if a template was created by saving a checklist from the issue view.

Please execute those queries one by one (based on your type of database):
PostgreSQL

1. Detect templates with duplicated items
   SELECT "ID" as tempalte_id, "NAME" as template_name, "CHECKLIST_ID" as "CHECKLIST_ID" FROM "AO_C2A220_TEMPLATE" acat
WHERE "CHECKLIST_ID" IN (
SELECT sub."CHECKLIST_ID"
FROM ( SELECT "CHECKLIST_ID", "VALUE", COUNT("VALUE") AS count_values
FROM "AO_C2A220_ITEM" acai
GROUP BY "CHECKLIST_ID", "VALUE"
) AS sub
GROUP BY sub."CHECKLIST_ID"
HAVING COUNT(sub."VALUE") = SUM(sub.count_values) / 2 );

2. Delete item details. The checklist ids can be found in result of the first query.
   delete from "AO_C2A220_QUOTE" where "ITEM_ID" in (
select min from( SELECT MIN("ID"),"CHECKLIST_ID", "VALUE", COUNT("VALUE") AS count_values
FROM "AO_C2A220_ITEM" acai
GROUP BY "CHECKLIST_ID", "VALUE"
having COUNT("VALUE") > 1
-- and "CHECKLIST_ID" = 11 -- ADD THIS CONDITION ALSO TO delete checklist by checklist, not all at once ) ) ;
   where for "CHECKLIST_ID" = 11 replace 11 with the value from the first query

3. Delete duplicate items. The checklist ids can be found in result of the first query.
   delete from "AO_C2A220_ITEM" where "ID" IN(
select min from(
SELECT MIN("ID"),"CHECKLIST_ID", "VALUE", COUNT("VALUE") AS count_values
FROM "AO_C2A220_ITEM" acai
GROUP BY "CHECKLIST_ID", "VALUE"
having COUNT("VALUE") > 1
-- and "CHECKLIST_ID" = 11 -- ADD THIS CONDITION ALSO TO delete checklist by checklist, not all at once ) );
   where for "CHECKLIST_ID" = 11 replace 11 with the value from the first query

4. Repeat step 2 and 3 (using "CHECKLIST_ID" = your value) as many times as there were templates found in the first query
   

Oracle

1. Detect templates with duplicated items
   SELECT "ID" AS template_id, "NAME" AS template_name, "CHECKLIST_ID"
FROM "AO_C2A220_TEMPLATE" acat
WHERE "CHECKLIST_ID" IN (
SELECT sub."CHECKLIST_ID"
FROM (
SELECT "CHECKLIST_ID", "VALUE", COUNT("VALUE") AS count_values
FROM "AO_C2A220_ITEM" acai
GROUP BY "CHECKLIST_ID", "VALUE"
) sub
GROUP BY sub."CHECKLIST_ID"
HAVING COUNT(sub."VALUE") = SUM(sub.count_values) / 2 );

2. Delete item details. The checklist ids can be found in the result of the first query.
   DELETE FROM "AO_C2A220_QUOTE"
WHERE "ITEM_ID" IN (
SELECT min_id FROM (
SELECT MIN("ID") AS min_id, "CHECKLIST_ID", "VALUE", COUNT("VALUE") AS count_values FROM "AO_C2A220_ITEM" acai
GROUP BY "CHECKLIST_ID", "VALUE"
HAVING COUNT("VALUE") > 1
-- AND "CHECKLIST_ID" = 11 ) );
   where for "CHECKLIST_ID" = 11 replace 11 with the value from the first query

3. Delete duplicate items. The checklist ids can be found in the result of the first query.
   DELETE FROM "AO_C2A220_ITEM"
WHERE "ID" IN (
SELECT min_id FROM (
SELECT MIN("ID") AS min_id, "CHECKLIST_ID", "VALUE", COUNT("VALUE") AS count_values FROM "AO_C2A220_ITEM" acai
GROUP BY "CHECKLIST_ID", "VALUE"
HAVING COUNT("VALUE") > 1
-- AND "CHECKLIST_ID" = 11 ) );
   where for "CHECKLIST_ID" = 11 replace 11 with the value from the first query

4. Repeat step 2 and 3 (using "CHECKLIST_ID" = your value) as many times as there were templates found in the first query
   

MySQL

1. Detect templates with duplicated items
   SELECT `ID` AS template_id, `NAME` AS template_name, `CHECKLIST_ID`
FROM `AO_C2A220_TEMPLATE` acat
WHERE `CHECKLIST_ID` IN (
SELECT sub.`CHECKLIST_ID`
FROM (
SELECT `CHECKLIST_ID`, `VALUE`, COUNT(`VALUE`) AS count_values
FROM `AO_C2A220_ITEM` acai
GROUP BY `CHECKLIST_ID`, `VALUE`
) sub
GROUP BY sub.`CHECKLIST_ID`
HAVING COUNT(sub.`VALUE`) = SUM(sub.count_values) / 2 );

2. Delete item details. The checklist ids can be found in the result of the first query.
   DELETE FROM `AO_C2A220_QUOTE`
WHERE `ITEM_ID` IN (
SELECT min_id FROM (
SELECT MIN(`ID`) AS min_id, `CHECKLIST_ID`, `VALUE`, COUNT(`VALUE`) AS count_values FROM `AO_C2A220_ITEM` acai
GROUP BY `CHECKLIST_ID`, `VALUE`
HAVING COUNT(`VALUE`) > 1
-- AND `CHECKLIST_ID` = 11 ) AS subquery );
   where for "CHECKLIST_ID" = 11 replace 11 with the value from the first query

3. Delete duplicate items. The checklist ids can be found in the result of the first query.
   DELETE FROM `AO_C2A220_ITEM`
WHERE `ID` IN (
SELECT min_id FROM ( SELECT MIN(`ID`) AS min_id, `CHECKLIST_ID`, `VALUE`, COUNT(`VALUE`) AS count_values
FROM `AO_C2A220_ITEM` acai
GROUP BY `CHECKLIST_ID`, `VALUE`
HAVING COUNT(`VALUE`) > 1
-- AND `CHECKLIST_ID` = 11 ) AS subquery );
   where for "CHECKLIST_ID" = 11 replace 11 with the value from the first query

4. Repeat step 2 and 3 (using "CHECKLIST_ID" = your value) as many times as there were templates found in the first query

Microsoft SQL

1. Detect templates with duplicated items
   SELECT [ID] AS template_id, [NAME] AS template_name, [CHECKLIST_ID]
FROM [AO_C2A220_TEMPLATE] acat
WHERE [CHECKLIST_ID] IN (
SELECT sub.[CHECKLIST_ID]
FROM (
SELECT [CHECKLIST_ID], [VALUE], COUNT([VALUE]) AS count_values
FROM [AO_C2A220_ITEM] acai
GROUP BY [CHECKLIST_ID], [VALUE]
) sub
GROUP BY sub.[CHECKLIST_ID]
HAVING COUNT(sub.[VALUE]) = SUM(sub.count_values) / 2 );

2. Delete item details. The checklist ids can be found in the result of the first query.
   DELETE FROM [AO_C2A220_QUOTE]
WHERE [ITEM_ID] IN (
SELECT min_id FROM (
SELECT MIN([ID]) AS min_id, [CHECKLIST_ID], [VALUE], COUNT([VALUE]) AS count_values FROM [AO_C2A220_ITEM] acai
GROUP BY [CHECKLIST_ID], [VALUE]
HAVING COUNT([VALUE]) > 1
-- AND [CHECKLIST_ID] = 11 ) AS subquery );
   where for "CHECKLIST_ID" = 11 replace 11 with the value from the first query

3. Delete duplicate items. The checklist ids can be found in the result of the first query.
   DELETE FROM [AO_C2A220_ITEM]
WHERE [ID] IN (
SELECT min_id FROM (
SELECT MIN([ID]) AS min_id, [CHECKLIST_ID], [VALUE], COUNT([VALUE]) AS count_values FROM [AO_C2A220_ITEM] acai
GROUP BY [CHECKLIST_ID], [VALUE]
HAVING COUNT([VALUE]) > 1
-- AND [CHECKLIST_ID] = 11 ) AS subquery );
   where for "CHECKLIST_ID" = 11 replace 11 with the value from the first query

4. Repeat step 2 and 3 (using "CHECKLIST_ID" = your value) as many times as there were templates found in the first query

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